There are various types of triangles among them some are said to be special, 30-60-90 are among them. We usually address a triangle as right-angled if one of the angles is 90°. Therefore, we can say that 30-60-90 is a special type of right-angled triangle. This type of triangle will always have its angles of 30°, 60°, and 90°.
30-60-90 Formula
The below figure represents the 30-60-90 triangle with ∠A = 60°, ∠B = 90°and ∠C = 30°. The 30-60-90 is pronounced as “thirty – sixty – ninety”.
30-60-90 Triangle
The side representing opposite to the angle 30° holds the smallest value and let it be “a” cm. Another side representing opposite to the angle 60° holds the moderate value and it is “a√3” cm. Lastly, the side representing opposite to the angle 90° holds the largest value and it is “2a” cm.
From the below figure,
- AB = a cm (Opposite to the angle 30°) ⇢ Shortest side
- BC = a√3 cm (Opposite to the angle 60°) ⇢ Intermediate side
- AC = 2a cm (Opposite to the angle 90°) ⇢ Largest side
Hence, AB:BC:CA = a:√3a:2a
Negating “a” since it is common. Now, look at the ratio of sides of 30-60-90 triangle i.e., 1:√3:2.
To prove this let’s consider an equilateral triangle i.e., the triangle in which all the sides are of the same length, and let it be “a” cm.
Let’s first consider the equilateral triangle (all sides being equal and making an angle of 60° at vertices) as shown in the figure. If we draw a line from one of the vertexes (say A) to the other side (say BC). Then the other side i.e., BC is divided into 2 equal halves (each part with a/2) and makes an angle of 90°. Let the dividing point or the midpoint of BC be D. Due to the line that is drawn the angle at the vertex A which is 60° will also be divided equally and each part holds 30°.
Now look at the half part of the figure which is triangle ABD, it resembles a 30-60-90 triangle with sides AB = a cm, BD = a/2 cm, AD = unknown (say x cm)
To find the value of AD let’s use the Pythagoras theorem, which states that “In a right-angled triangle, the square of the hypotenuse side (longest side) is equal to the sum of squares of the other two sides“, from the figure AB is the hypotenuse, BD and AD are other 2 sides.
Therefore,
AB2 = BD2 + AD2
a2 = (a/2)2 + x2
x2 = a2 – (a/2)2
x = √3a/2 cm (AD)
The ratio of the sides that are opposite to the angles 30-60-90 will be a/2: √3a/2: a ⇒ 1:√3:2 (taking as common and neglecting it and multiplying with 2)
This ratio 1:√3:2 is known as the 30-60-90 formula
Area of 30-60-90 Triangle
To find the area of 30-60-90 let’s consider the common formula for the area of triangle i.e., = 1/2 × base × height
For the triangle, ABD, AD act as height (√3a/2 cm), and BD act as a base (a/2)
Therefore the area of triangle =1/2 × a/2 × √3a/2
Area = √3a2/8
Sample Problems
Question 1: If the 2 of the sides of the 30-60-90 triangle are 20 cm and 40 cm, find the other side.
Solution:
Given 2 sides are 20 and 40, which are in the ratio of 1:2
To find the third side i.e., x from the 30-60-90 formula 1:√3:2 x ⇒ √3a
x ⇒ 20 × √3 cm.
x = 20√3cm
Question 2: The shortest side of the 30-60-90 is 40cm, find the area of the triangle?
Solution:
In a 30-60-90 triangle, the sides are in a specific ratio. The side opposite the 30-degree angle is half the length of the hypotenuse, and the side opposite the 60-degree angle is √3/2 times the length of the hypotenuse.
Given that the shortest side is 40 cm, we can use this information to find the lengths of the other sides.
Let ( x ) be the length of the shortest side (opposite the 30-degree angle), then the lengths of the other sides are:
- – The length of the medium side (opposite the 60-degree angle) is x√3
- – The length of the longest side (the hypotenuse) is ( 2x ).
We’re given that the shortest side is 40 cm. So, ( x = 40 ) cm.
- – The length of the medium side is 40√3 cm.
- – The length of the longest side (hypotenuse) is ( 2 x 40 = 80 ) cm.
Now, to find the area of the triangle, we can use the formula:
Area = 1/2 x base x height
In a 30-60-90 triangle, the base (shortest side) is opposite the 30-degree angle, and the height is opposite the 60-degree angle.
So, the area is:
Area = 1/2 x 40 x 40√3
Area = 20 x 40√3
Area = 800√3
Thus, the area of the triangle is 800√3 square centimeters.
Question 3: The longest side of the 30-60-90 is 120cm, find the area of the triangle?
Solution:
Given the longest side is 120cm i.e., 2a = 120 cm.
Therefore, a = 60 cm.
Area of 30-60-90 is given as (√3 × a2)/8
Therefore Area ⇒ (√3 × 60 × 60) / 8
⇒ 450√3 cm2.
Question 4: The moderate side of the 30-60-90 is 12√3cm, find the area of the triangle?
Solution:
Given the moderate side is 120cm i.e., a√3 = 12√3 cm.
Therefore, a = 12 cm.
Area of 30-60-90 is given as (√3 × a2)/8
Therefore Area ⇒ (√3 × 12 × 12) / 8
⇒ 18√3 cm2.
Question 5: The shortest side of the triangle is 90 cm, find the longest side?
Solution:
Given the shortest side of 30-60-90 is 90 cm.
From the 30-60-90 formula the shortest and longest sides are in the ratio 1:2 ⇒ x:2x
Given x = 90 2x = ?
Therefore, 2x = 2 × 90 = 180 cm.
Question 6: The longest side of the triangle is 20cm, find the intermediate side length?
Solution:
Given the longest side of 30-60-90 is 20 cm.
From 30-60-90 formula the longest and intermediate sides are in the ratio 2:√3 ⇒ 2x :√3 x
Given 2x = 20
x = 10
Therefore, √3x = √3 × 10 = 10√3 cm.